![SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge](https://cdn.numerade.com/ask_images/65e0695970c94c1da974f651bed9d0da.jpg)
SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge
![Given that P=Q=R. If vec(P)+vec(Q)=vec(R) then the angle between vec(P) and vec(R) is theta(1). If vec(P)+vec(Q)+vec(R)=vec(0) then the angle between vec(P) and vec(R) is theta(2). The relation between theta(1) and theta(2) is :- Given that P=Q=R. If vec(P)+vec(Q)=vec(R) then the angle between vec(P) and vec(R) is theta(1). If vec(P)+vec(Q)+vec(R)=vec(0) then the angle between vec(P) and vec(R) is theta(2). The relation between theta(1) and theta(2) is :-](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/642715325_web.png)
Given that P=Q=R. If vec(P)+vec(Q)=vec(R) then the angle between vec(P) and vec(R) is theta(1). If vec(P)+vec(Q)+vec(R)=vec(0) then the angle between vec(P) and vec(R) is theta(2). The relation between theta(1) and theta(2) is :-
![If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to - If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -](https://dwes9vv9u0550.cloudfront.net/images/3952961/792dfa8e-ee2a-4599-8b84-b82c9bb1d049.jpg)
If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -
![So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart? So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?](https://external-preview.redd.it/7EXbmtiqKJm9vW-oXNDRUdM2p9efEPP8QVYep10VtXg.jpg?auto=webp&s=340cdc1a658097201327a258cb96aa518f97be2d)
So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?
![triangle PQR with side p across from angle P, side q across from angle Q, and side r across from - Brainly.com triangle PQR with side p across from angle P, side q across from angle Q, and side r across from - Brainly.com](https://us-static.z-dn.net/files/d99/18d9232adbaf996c2ada6011f07dbe55.png)